#include #include #include #include #include #include int *dec_to_bin(int d, int *length) { int *binary_form = calloc(20, sizeof(int)); int index = 0; while (d != 0) { binary_form[index] = d % 2; d /= 2; index++; } *length = index; for (int i = index; i >= 0; i--) { printf("%d", binary_form[i]); } printf(" index: %d\n", index); return binary_form; } uint64_t quick_pow(int *d_binary, int a, int n, int length) { uint64_t *powed = calloc(20, sizeof(uint64_t)); powed[0] = a; for (int i = 1; i <= length; i++) { powed[i] = (powed[i - 1] * powed[i - 1]) % n; printf("powed: %ju, index: %d; ", powed[i], (i)); } // check where in the binary are ones uint64_t multiplied = 1; for (int i = 0; i < length; i++) { if (d_binary[i] == 1) { multiplied *= powed[i]; } } printf("\nbm quick math: %ju; %d ", multiplied, n); multiplied = multiplied % n; printf("quick math: %ju", multiplied); free(powed); return multiplied; } bool prime_test(uint64_t n) { printf("\n\nprime test: %jd\n", n); // Miller Rabin prime test // choose a base: a, which should be a prime so that (n, a) = 1 // then do 2 rounds of tests provided the first one did not fail // 1: a^d =k 1 mod n // 2: a^(d * 2^r) =k n-1 mod n // d = n-1 / 2^S (where S means how many time did we divide the number till we reached the first odd number) // S: see above // r = {0,... S-1} int a = 2; int d = n - 1; int S = 0; int r = S - 1; // this stores the number of elements from 0 to S-1 while (d % 2 == 0) { d = floor((double)d / 2.0); S++; printf("%d ", d); } printf("S: %d", S); printf("\n"); // round 1 // 1: a^d =k 1 mod n int length; int *d_binary = dec_to_bin(d, &length); if (quick_pow(d_binary, a, n, length) == 1) { free(d_binary); return true; } printf("\n\n"); free(d_binary); return false; } int main() { prime_test(111); prime_test(29); prime_test(27); return 0; }