working quick_pow dec_to_bin
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94
main.c
94
main.c
@@ -1,6 +1,98 @@
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#include <inttypes.h>
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#include <math.h>
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#include <stdbool.h>
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#include <stdint.h>
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#include <stdio.h>
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#include <stdlib.h>
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int *dec_to_bin(int d, int *length) {
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int *binary_form = calloc(20, sizeof(int));
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int index = 0;
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while (d != 0) {
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binary_form[index] = d % 2;
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d /= 2;
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index++;
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}
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*length = index;
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for (int i = index; i >= 0; i--) {
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printf("%d", binary_form[i]);
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}
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printf(" index: %d\n", index);
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return binary_form;
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}
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uint64_t quick_pow(int *d_binary, int a, int n, int length) {
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uint64_t *powed = calloc(20, sizeof(uint64_t));
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powed[0] = a;
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for (int i = 1; i <= length; i++) {
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powed[i] = (powed[i - 1] * powed[i - 1]) % n;
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printf("powed: %ju, index: %d; ", powed[i], (i));
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}
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// check where in the binary are ones
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uint64_t multiplied = 1;
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for (int i = 0; i < length; i++) {
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if (d_binary[i] == 1) {
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multiplied *= powed[i];
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}
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}
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printf("\nbm quick math: %ju; %d ", multiplied, n);
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multiplied = multiplied % n;
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printf("quick math: %ju", multiplied);
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free(powed);
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return multiplied;
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}
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bool prime_test(uint64_t n) {
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printf("\n\nprime test: %jd\n", n);
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// Miller Rabin prime test
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// choose a base: a, which should be a prime so that (n, a) = 1
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// then do 2 rounds of tests provided the first one did not fail
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// 1: a^d =k 1 mod n
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// 2: a^(d * 2^r) =k n-1 mod n
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// d = n-1 / 2^S (where S means how many time did we divide the number till we reached the first odd number)
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// S: see above
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// r = {0,... S-1}
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int a = 2;
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int d = n - 1;
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int S = 0;
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int r = S - 1; // this stores the number of elements from 0 to S-1
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while (d % 2 == 0) {
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d = floor((double)d / 2.0);
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S++;
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printf("%d ", d);
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}
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printf("S: %d", S);
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printf("\n");
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// round 1
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// 1: a^d =k 1 mod n
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int length;
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int *d_binary = dec_to_bin(d, &length);
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if (quick_pow(d_binary, a, n, length) == 1) {
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free(d_binary);
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return true;
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}
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printf("\n\n");
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free(d_binary);
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return false;
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}
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int main() {
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printf("Hello world!");
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prime_test(111);
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prime_test(29);
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prime_test(27);
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return 0;
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}
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